PHƯƠNG TRÌNH HƠP TÍCH HAI SỐ HẠNG BẬC 2
( Với phương trình giải : ax2 + c = 0 )
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TỐC SOẠN TOÁN HỌC giới thiệu thêm một số phương trình hợp
tích được soạn sẳn để các bạn yêu thích toán học, nếu cần, có thể tùy
nghi sử dụng :
1) a. (40x+ 122)(25x +66) – (27x+83)(37x+97) = 0 => x2 + 1 = 0
b. (196x+ 573)(52x +149) – (79x+232)(129x+368) = 0 => x2 + 1 = 0
2) a. (107x+257)(107x+305) – (212x+509)(54x+154) = 0 => x2 – 1 = 0
b.(191x+829)(171x+731)–(115x+500)(284x+1212) = 0 => x2 – 1 = 0
3) a. (81x+ 150)(41x +112) – (83x+227)(40x+74) = 0 => x2 + 2 = 0
b. (33x+ 88)(67x +232) – (34x+118)(65x+173) = 0 => x2 + 2 = 0
4) a. (49x+ 184)(24x +97) – (47x+175)(25x+102) = 0 => x2 – 2 = 0
b. (29x+ 80)(59x +208) – (30x+106)(57x+157) = 0 => x2 – 2 = 0
5) a. (41x+ 111)(164x +373) – (81x+184)(83x+225) = 0 => x2 + 3 = 0
b. (13x+ 37)(27x +84) – (14x+45)(25x+69) = 0 => x2 + 3 = 0
6) a. (47x+ 162)(24x +98) – (49x+201)(23x+79) = 0 => x2 – 3 = 0
b. (29x+ 81)(59x +210) – (30x+107)(57x+159) = 0 => x2 –3 = 0
7) a. (27x+ 62)(13x +32) – (25x+55)(14x+36) = 0 => x2 + 4 = 0
b. (27x+ 47)(14x +20) – (29x+52)(13x+18) = 0 => x2 + 4 = 0
8) a. (29x+ 92)(14x +37) – (27x+71)(15x+48) = 0 => x2 – 4 = 0
b. (9x+ 22)(19x +52) – (10x+28)(17x+41) = 0 => x2 –4 = 0
9) a. (32x+ 54)(23x +50) – (35x+77)(21x+35) = 0 => x2 + 5 = 0
b. (11x+ 19)(47x +104) – (12x+27)(43x+73) = 0 => x2 + 5 = 0
10) a. (27x+ 55)(13x +29) – (25x+50)(14x+32) = 0 => x2 – 5 = 0
b. (10x+ 21)(21x +55) – (11x+29)(19x+40) = 0 => x2 –5= 0
11) a. (31x+ 48)(11x +22) – (34x+70)(10x+15) = 0 => x2 + 6 = 0
b. (21x+ 43)(21x +42) – (11x+24)(40x+75) = 0 => x2 + 6 = 0
12) a. (21x+ 67)(10x +30) – (19x+56)(11x+36) = 0 => x2 – 6 = 0
b. (32x+ 103)(39x +116) – (29x+86)(43x+139) = 0 => x2 –6 = 0
13) a. (33x+ 17)(17x +23) – (35x+48)(16x+8) = 0 => x2 + 7 = 0
b. (16x+ 32)(33x +56) – (17x+35)(31x+51) = 0 => x2 + 7 = 0
14) a. (9x+ 25)(19x +58) – (10x+31)(17x+47) = 0 => x2 – 7 = 0
b. (23x+ 79)(11x +35) – (21x+66)(12x+42) = 0 => x2 –7 = 0
15) a. (27x+ 42)(55x +62) – (28x+44)(53x+59) = 0 => x2 + 8 = 0
b. (13x+ 22)(27x +39) – (14x+25)(25x+34) = 0 => x2 + 8 = 0
16) a. (14x+ 48)(25x +73) – (13x+38)(27x+92) = 0 => x2 – 8 = 0
b. (10x+ 33)(21x +70) – (11x+38)(19x+61) = 0 => x2 –8 = 0
17) a. (23x+ 27)(32x +37) – (21x+22)(35x+45) = 0 => x2 + 9 = 0
b. (23x+ 47)(11x +19) – (21x+34)(12x+26) = 0 => x2 + 9 = 0
18) a. (10x+ 30)(21x +70) – (11x+37)(19x+57) = 0 => x2 – 9 = 0
b. (23x+ 61)(17x +51) – (26x+78)(15x+40) = 0 => x2 – 9 = 0
19) a. (19x+ 25)(31x +58) – (21x+40)(28x+36) = 0 => x2 + 10= 0
b. (13x+ 30)(27x +61) – (14x+35)(25x+52) = 0 => x2 + 10 = 0
20) a. (12x+ 30)(25x +53) – (13x+32)(23x+50) = 0 => x2 – 10 = 0
b. (12x+ 37)(38x +110) – (13x+40)(35x+102) = 0 => x2 –10 = 0
(Soạn ngày : 18/3/2013)
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